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UPSC CSE CSAT 2018 · Paper II (CSAT) · Question 6 · Arithmetic: percentage, ratio, averages, time & work

200 मीटर लम्बी एक ट्रेन 40 कि॰ मी॰ प्रति घंटा की दर से चल रही है। रेलवे लाइन के निकट खड़े किसी…

UPSC Civil Services (Preliminary) Examination 2018, General Studies Paper II (CSAT), Question 6 — Arithmetic: percentage, ratio, averages, time & work.

200 मीटर लम्बी एक ट्रेन 40 कि॰ मी॰ प्रति घंटा की दर से चल रही है। रेलवे लाइन के निकट खड़े किसी व्यक्ति को यह ट्रेन कितने सेकंड में पार करेगी?

Read this question in English

A train 200 metres long is moving at the rate of 40 kmph. In how many seconds will it cross a man standing near the railway line?

(a) 12 · (b) 15 · (c) 16 · (d) 18

उत्तर और व्याख्या · explanation in English

Answer: (d) 18

To pass a man standing still, the train covers only its own length, 200 m. At 40 km/h, which is 100/9 m/s, that takes 18 seconds.

  1. Distance to cover = length of the train = 200 m (the man adds no length).
  2. Speed: 40 km/h = 40 × 5/18 = 100/9 m/s.
  3. Time = 200 ÷ (100/9) = 18 seconds.
  4. Check: in 18 s at 40 km/h the train covers 40,000 × 18 ÷ 3600 = 200 m.

Remember · A train passing a pole or a standing person covers only its own length; convert km/h to m/s by multiplying by 5/18.

Question and answer: UPSC's official GS Paper II (2018, Series A) — paper ↗ · answer key ↗. Explanation: Minimalist IAS, checked 30 Sept 2026 (how we verify). ·

Cite this question: UPSC CSE CSAT 2018, Q6 — minimalistias.com/pyqs/csat/2018/q6

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