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UPSC CSE CSAT 2018 · Paper II (CSAT) · Question 6 · Arithmetic: percentage, ratio, averages, time & work

A train 200 metres long is moving at the rate of 40 kmph. In how many seconds will it cross a man…

UPSC Civil Services (Preliminary) Examination 2018, General Studies Paper II (CSAT), Question 6 — Arithmetic: percentage, ratio, averages, time & work.

A train 200 metres long is moving at the rate of 40 kmph. In how many seconds will it cross a man standing near the railway line?

Answer & explanation

Answer: (d) 18

To pass a man standing still, the train covers only its own length, 200 m. At 40 km/h, which is 100/9 m/s, that takes 18 seconds.

  1. Distance to cover = length of the train = 200 m (the man adds no length).
  2. Speed: 40 km/h = 40 × 5/18 = 100/9 m/s.
  3. Time = 200 ÷ (100/9) = 18 seconds.
  4. Check: in 18 s at 40 km/h the train covers 40,000 × 18 ÷ 3600 = 200 m.

Remember · A train passing a pole or a standing person covers only its own length; convert km/h to m/s by multiplying by 5/18.

Question and answer: UPSC's official GS Paper II (2018, Series A) — paper ↗ · answer key ↗. Explanation: Minimalist IAS, checked 30 Sept 2026 (how we verify). ·

Cite this question: UPSC CSE CSAT 2018, Q6 — minimalistias.com/pyqs/csat/2018/q6

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