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UPSC CSE CSAT 2026 · Paper II (CSAT) · Question 56 · Logical & analytical reasoning

पूर्व दिशा की ओर अभिमुखित एक व्यक्ति 4 km सीधा चलता है और उसके बाद दाईं ओर मुड़ता है तथा 3 km चलता…

UPSC Civil Services (Preliminary) Examination 2026, General Studies Paper II (CSAT), Question 56 — Logical & analytical reasoning.

CSAT 2026 · Q56

Logical & analytical reasoning Easy Provisional key

पूर्व दिशा की ओर अभिमुखित एक व्यक्ति 4 km सीधा चलता है और उसके बाद दाईं ओर मुड़ता है तथा 3 km चलता है, फिर बाईं ओर मुड़ता है और 2 km चलता है और अंत में, बाईं ओर मुड़ता है और 3 km चलता है। अंतिम स्थान और आरंभिक स्थान के बीच की न्यूनतम दूरी, तथा अंतिम स्थान पर जिस दिशा की ओर व्यक्ति अभिमुखित है, वे क्रमशः हैं

Read this question in English

A person facing the East travels 4 km straight and then turns right and travels 3 km, then further turns left and travels 2 km and finally turns left and travels 3 km. The minimum distance between the final point and the initial point, and the direction in which the person is facing at the final point are, respectively

(a) 12 km, East · (b) 6 km, East · (c) 8 km, North · (d) 6 km, North

उत्तर और व्याख्या · explanation in English

Answer: (d) 6 km, उत्तर

Track each turn: East 4 km, right to South 3 km, left to East 2 km, left to North 3 km. The south and north legs cancel, leaving the person 6 km east of the start, facing North.

  1. Start facing East: 4 km East.
  2. Turn right → South: 3 km South.
  3. Turn left → East: 2 km East.
  4. Turn left → North: 3 km North.
  5. Net: 4 + 2 = 6 km East; 3 South − 3 North = 0. Distance 6 km, facing North.

Remember · Direction items: write the facing direction after every turn, then net out opposite legs.

Question and answer: UPSC's provisional GS Paper II (2026, Series A) — paper ↗ · answer key ↗. Explanation: Minimalist IAS, checked 30 Sept 2026 (how we verify). ·

Cite this question: UPSC CSE CSAT 2026, Q56 — minimalistias.com/pyqs/csat/2026/q56

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