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UPSC CSE CSAT 2020 · Paper II (CSAT) · Question 69 · Arithmetic: percentage, ratio, averages, time & work

एक बल्लेबाज का उसकी 50वीं पारी के बाद औसत स्कोर 46·4 था। 60वीं पारी के बाद, उसका औसत स्कोर 2·6 बढ़…

UPSC Civil Services (Preliminary) Examination 2020, General Studies Paper II (CSAT), Question 69 — Arithmetic: percentage, ratio, averages, time & work.

एक बल्लेबाज का उसकी 50वीं पारी के बाद औसत स्कोर 46·4 था। 60वीं पारी के बाद, उसका औसत स्कोर 2·6 बढ़ जाता है। पिछली दस पारियों में उसका औसत स्कोर क्या था?

Read this question in English

The average score of a batsman after his 50th innings was 46.4. After 60th innings, his average score increases by 2.6. What was his average score in the last ten innings?

(a) 122 · (b) 91 · (c) 62 · (d) 49

उत्तर और व्याख्या · explanation in English

Answer: (c) 62

Turn both averages into totals: 50 × 46·4 = 2320 and 60 × 49 = 2940. The last ten innings added 620 runs, an average of 62.

  1. Runs after 50 innings = 50 × 46·4 = 2320.
  2. New average = 46·4 + 2·6 = 49; runs after 60 innings = 60 × 49 = 2940.
  3. Runs in the last 10 innings = 2940 − 2320 = 620.
  4. Average of the last 10 = 620 ÷ 10 = 62.

Remember · Averages over different counts: convert each to a total, subtract, and divide by the new count.

Question and answer: UPSC's official GS Paper II (2020, Series A) — paper ↗ · answer key ↗. Explanation: Minimalist IAS, checked 30 Sept 2026 (how we verify). ·

Cite this question: UPSC CSE CSAT 2020, Q69 — minimalistias.com/pyqs/csat/2020/q69

In the UPSC syllabus: Arithmetic: percentage, ratio, averages, time & work › Averages & ages See it and tick it covered →

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