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UPSC CSE CSAT 2019 · Paper II (CSAT) · Question 34 · Arithmetic: percentage, ratio, averages, time & work

किसी परीक्षा में, A ने B से 20 अंक अधिक प्राप्त किए हैं । यदि B ने A से 5% कम अंक प्राप्त किए हों,…

UPSC Civil Services (Preliminary) Examination 2019, General Studies Paper II (CSAT), Question 34 — Arithmetic: percentage, ratio, averages, time & work.

किसी परीक्षा में, A ने B से 20 अंक अधिक प्राप्त किए हैं । यदि B ने A से 5% कम अंक प्राप्त किए हों, तो B ने कितने अंक प्राप्त किए हैं ?

Read this question in English

In an examination, A has scored 20 marks more than B. If B has scored 5% less marks than A, how much has B scored?

(a) 360 · (b) 380 · (c) 400 · (d) 420

उत्तर और व्याख्या · explanation in English

Answer: (b) 380

B's shortfall of 5% is measured on A's marks and equals the 20-mark gap, so A has 400 and B 380.

  1. B = A − 20, and B = 95% of A.
  2. So 5% of A = 20, giving A = 400.
  3. B = 400 − 20 = 380.
  4. Check: 95% of 400 = 380.

Remember · When a percentage gap equals a known difference, that difference is the percentage of the base.

Question and answer: UPSC's official GS Paper II (2019, Series A) — paper ↗ · answer key ↗. Explanation: Minimalist IAS, checked 30 Sept 2026 (how we verify). ·

Cite this question: UPSC CSE CSAT 2019, Q34 — minimalistias.com/pyqs/csat/2019/q34

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