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UPSC CSE CSAT 2018 · Paper II (CSAT) · Question 69 · Arithmetic: percentage, ratio, averages, time & work

किसी व्यक्ति ने ₹22,800 कीमत का रेफ्रीजरेटर 12·5% चक्रवृद्धि ब्याज (वार्षिक) पर खरीदा। पहले वर्ष…

UPSC Civil Services (Preliminary) Examination 2018, General Studies Paper II (CSAT), Question 69 — Arithmetic: percentage, ratio, averages, time & work.

किसी व्यक्ति ने ₹22,800 कीमत का रेफ्रीजरेटर 12·5% चक्रवृद्धि ब्याज (वार्षिक) पर खरीदा। पहले वर्ष के अंत पर उसने ₹8,650 एवं दूसरे वर्ष के अंत पर ₹9,125 चुकाए। ऋण पूरा चुकाने के लिए उसे तीसरे वर्ष के अंत में कितने रुपये का भुगतान करना होगा?

Read this question in English

A person bought a refrigerator worth ₹22,800 with 12.5% interest compounded yearly. At the end of first year he paid ₹8,650 and at the end of second year ₹9,125. How much will he have to pay at the end of third year to clear the debt?

(a) ₹9,990 · (b) ₹10,000 · (c) ₹10,590 · (d) ₹11,250

उत्तर और व्याख्या · explanation in English

Answer: (d) ₹11,250

Add a year's interest (12.5%, one-eighth) to the balance and subtract each payment. The balance falls to ₹17,000 after year 1 and ₹10,000 after year 2, so year 3 needs ₹10,000 × 1.125 = ₹11,250.

  1. Year 1: 22,800 × 1.125 = 25,650; after paying 8,650 the balance is 17,000.
  2. Year 2: 17,000 × 1.125 = 19,125; after paying 9,125 the balance is 10,000.
  3. Year 3: 10,000 × 1.125 = 11,250 clears the debt.
  4. Check: ₹10,000 is only the balance at the start of year 3; it still earns a year's interest.

Remember · For instalments at compound interest, roll the balance forward: add the year's interest, subtract the payment. 12.5% is one-eighth.

Question and answer: UPSC's official GS Paper II (2018, Series A) — paper ↗ · answer key ↗. Explanation: Minimalist IAS, checked 30 Sept 2026 (how we verify). ·

Cite this question: UPSC CSE CSAT 2018, Q69 — minimalistias.com/pyqs/csat/2018/q69

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