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UPSC CSE CSAT 2018 · Paper II (CSAT) · Question 41 · Arithmetic: percentage, ratio, averages, time & work

किसी परीक्षा में पास होने के लिए एक विद्यार्थी को 40% अंक चाहिए। मान लीजिए कि उसे 30 अंक मिलते हैं…

UPSC Civil Services (Preliminary) Examination 2018, General Studies Paper II (CSAT), Question 41 — Arithmetic: percentage, ratio, averages, time & work.

किसी परीक्षा में पास होने के लिए एक विद्यार्थी को 40% अंक चाहिए। मान लीजिए कि उसे 30 अंक मिलते हैं तथा वह 30 अंकों से अनुत्तीर्ण हो जाता है, तो परीक्षा में अधिकतम अंक कितने हैं?

Read this question in English

A student has to get 40% marks to pass in an examination. Suppose he gets 30 marks and fails by 30 marks, then what are the maximum marks in the examination?

(a) 100 · (b) 120 · (c) 150 · (d) 300

उत्तर और व्याख्या · explanation in English

Answer: (c) 150

Scoring 30 and falling 30 short means the pass mark is 60. If 60 is 40% of the maximum, the maximum is 60 ÷ 0.4 = 150.

  1. Pass mark = marks scored + shortfall = 30 + 30 = 60.
  2. 40% of maximum = 60, so maximum = 60 × 100 ÷ 40 = 150.
  3. Check: 40% of 150 = 60, and 60 − 30 = 30.

Remember · Pass mark = marks scored + shortfall; divide it by the pass percentage to get the maximum marks.

Question and answer: UPSC's official GS Paper II (2018, Series A) — paper ↗ · answer key ↗. Explanation: Minimalist IAS, checked 30 Sept 2026 (how we verify). ·

Cite this question: UPSC CSE CSAT 2018, Q41 — minimalistias.com/pyqs/csat/2018/q41

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