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UPSC CSE CSAT 2016 · Paper II (CSAT) · Question 51 · Arithmetic: percentage, ratio, averages, time & work

5 सदस्यों वाले परिवार में 3 वर्ष पूर्व सभी सदस्यों की आयु का योग 80 वर्ष था। इस परिवार की 3 वर्ष…

UPSC Civil Services (Preliminary) Examination 2016, General Studies Paper II (CSAT), Question 51 — Arithmetic: percentage, ratio, averages, time & work.

5 सदस्यों वाले परिवार में 3 वर्ष पूर्व सभी सदस्यों की आयु का योग 80 वर्ष था। इस परिवार की 3 वर्ष पूर्व जो औसत आयु थी, आज भी वही है क्योंकि अन्तःस्थ अवधि में परिवार में एक शिशु की वृद्धि हुई। शिशु की आयु क्या है ?

Read this question in English

The sum of the ages of 5 members comprising a family, 3 years ago was 80 years. The average age of the family today is the same as it was 3 years ago, because of an addition of a baby during the intervening period. How old is the baby?

(a) 6 months · (b) 1 year · (c) 2 years · (d) 2 years and 6 months

उत्तर और व्याख्या · explanation in English

Answer: (b) 1 वर्ष

The five members now total 80 + 15 = 95 years. With the baby, six people must total 6 × 16 = 96 years to keep the average at 16, so the baby is 1 year old.

  1. Three years ago: 5 members, total 80, average 16.
  2. Today the same 5 total 80 + 5 × 3 = 95.
  3. Today 6 members average 16: total 6 × 16 = 96.
  4. Baby's age = 96 − 95 = 1 year.

Remember · Age totals grow by (number of people × years passed); compare the required total with the grown total.

Question and answer: UPSC's official GS Paper II (2016, Series A) — paper ↗ · answer key ↗. Explanation: Minimalist IAS, checked 30 Sept 2026 (how we verify). ·

Cite this question: UPSC CSE CSAT 2016, Q51 — minimalistias.com/pyqs/csat/2016/q51

In the UPSC syllabus: Arithmetic: percentage, ratio, averages, time & work › Averages & ages See it and tick it covered →

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