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UPSC CSE CSAT 2020 · Question 77 · Number system

A digit n > 3 is divisible by 3 but not divisible by 6. Which one of the following is divisible by…

CSAT 2020 · Q77

Number system Easy

A digit n > 3 is divisible by 3 but not divisible by 6. Which one of the following is divisible by 4?

Answer & explanation

Answer: (d) 3n + 1

The digits greater than 3 that are divisible by 3 are 6 and 9; 6 is divisible by 6, so n = 9. Then 3n + 1 = 28 is the only option divisible by 4.

  1. Digits above 3 divisible by 3: 6 and 9. 6 is divisible by 6, so n = 9.
  2. 2n = 18, 3n = 27, 2n + 4 = 22 — none divisible by 4.
  3. 3n + 1 = 28 = 4 × 7 — divisible by 4.

Remember · When a condition pins a single digit, find that digit first and then test every option numerically.

Question and answer: UPSC's official GS Paper II (2020, Series A) — paper ↗ · answer key ↗. Explanation: Minimalist IAS, checked 30 Sept 2026 (how we verify). ·

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