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UPSC CSE CSAT 2020 · Paper II (CSAT) · Question 77 · Number system

एक अंक n > 3 भाज्य है 3 से लेकिन 6 से भाज्य नहीं है। निम्नलिखित में से कौन-सा एक 4 से भाज्य है?

UPSC Civil Services (Preliminary) Examination 2020, General Studies Paper II (CSAT), Question 77 — Number system.

CSAT 2020 · Q77

Number system Easy

एक अंक n > 3 भाज्य है 3 से लेकिन 6 से भाज्य नहीं है। निम्नलिखित में से कौन-सा एक 4 से भाज्य है?

Read this question in English

A digit n > 3 is divisible by 3 but not divisible by 6. Which one of the following is divisible by 4?

(a) 2n · (b) 3n · (c) 2n + 4 · (d) 3n + 1

उत्तर और व्याख्या · explanation in English

Answer: (d) 3n+1

The digits greater than 3 that are divisible by 3 are 6 and 9; 6 is divisible by 6, so n = 9. Then 3n + 1 = 28 is the only option divisible by 4.

  1. Digits above 3 divisible by 3: 6 and 9. 6 is divisible by 6, so n = 9.
  2. 2n = 18, 3n = 27, 2n + 4 = 22 — none divisible by 4.
  3. 3n + 1 = 28 = 4 × 7 — divisible by 4.

Remember · When a condition pins a single digit, find that digit first and then test every option numerically.

Question and answer: UPSC's official GS Paper II (2020, Series A) — paper ↗ · answer key ↗. Explanation: Minimalist IAS, checked 30 Sept 2026 (how we verify). ·

Cite this question: UPSC CSE CSAT 2020, Q77 — minimalistias.com/pyqs/csat/2020/q77

In the UPSC syllabus: Number system › Divisibility, remainders, HCF & LCM See it and tick it covered →

Timed · 30 minutes Take CSAT Number system · Set 7 as a test This question is in it — with UPSC's marking and an instant score. Start the set

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