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UPSC CSE CSAT 2025 · Paper II (CSAT) · Question 78 · Arithmetic: percentage, ratio, averages, time & work

तीन संख्याओं p, q और r का औसत k है । p औसत से उतना अधिक है, जितना q औसत से कम है । r का मान क्या…

UPSC Civil Services (Preliminary) Examination 2025, General Studies Paper II (CSAT), Question 78 — Arithmetic: percentage, ratio, averages, time & work.

तीन संख्याओं p, q और r का औसत k है । p औसत से उतना अधिक है, जितना q औसत से कम है । r का मान क्या है ?

Read this question in English

The average of three numbers p, q and r is k. p is as much more than the average as q is less than the average. What is the value of r?

(a) k · (b) k − 1 · (c) k + 1 · (d) k/2

उत्तर और व्याख्या · explanation in English

Answer: (a) k

p is above the average by exactly the amount q is below it, so p and q together total 2k. Since all three total 3k, r must equal k.

  1. Let p = k + d. Then q is below k by the same amount: q = k − d.
  2. p + q = 2k, and p + q + r = 3k because the average is k.
  3. So r = 3k − 2k = k.
  4. Check: p = 7, q = 3, r = 5 has average 5 and r equals the average.

Remember · Deviations from an average always sum to zero; equal and opposite deviations leave the third number at the average.

Question and answer: UPSC's official GS Paper II (2025, Series A) — paper ↗ · answer key ↗. Explanation: Minimalist IAS, checked 30 Sept 2026 (how we verify). ·

Cite this question: UPSC CSE CSAT 2025, Q78 — minimalistias.com/pyqs/csat/2025/q78

In the UPSC syllabus: Arithmetic: percentage, ratio, averages, time & work › Averages & ages See it and tick it covered →

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