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UPSC CSE CSAT 2020 · Paper II (CSAT) · Question 79 · Arithmetic: percentage, ratio, averages, time & work

पानी से भरे हुए एक बर्तन का भार 40 kg है। यदि यह एक-तिहाई भरा हुआ है, तो इसका भार 20 kg हो ज़ाता…

UPSC Civil Services (Preliminary) Examination 2020, General Studies Paper II (CSAT), Question 79 — Arithmetic: percentage, ratio, averages, time & work.

पानी से भरे हुए एक बर्तन का भार 40 kg है। यदि यह एक-तिहाई भरा हुआ है, तो इसका भार 20 kg हो ज़ाता है। खाली बर्तन का भार क्या है?

Read this question in English

A vessel full of water weighs 40 kg. If it is one-third filled, its weight becomes 20 kg. What is the weight of the empty vessel?

(a) 10 kg · (b) 15 kg · (c) 20 kg · (d) 25 kg

उत्तर और व्याख्या · explanation in English

Answer: (a) 10 kg

Going from full to one-third full removes two-thirds of the water and 20 kg of weight, so the full water weighs 30 kg. The empty vessel is 40 − 30 = 10 kg.

  1. Full: vessel + water = 40 kg. One-third full: vessel + water/3 = 20 kg.
  2. Subtracting: (2/3) × water = 20 kg, so water = 30 kg.
  3. Empty vessel = 40 − 30 = 10 kg.
  4. Check: 10 + 30/3 = 20 kg.

Remember · Subtract the two readings: the difference belongs to the water alone, which fixes the water's full weight.

Question and answer: UPSC's official GS Paper II (2020, Series A) — paper ↗ · answer key ↗. Explanation: Minimalist IAS, checked 30 Sept 2026 (how we verify). ·

Cite this question: UPSC CSE CSAT 2020, Q79 — minimalistias.com/pyqs/csat/2020/q79

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