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UPSC CSE CSAT 2019 · Paper II (CSAT) · Question 38 · Arithmetic: percentage, ratio, averages, time & work

ईना अपने माता-पिता के विवाह के 4 वर्ष बाद पैदा हुई । उसकी माता उसके पिता से तीन वर्ष छोटी है और…

UPSC Civil Services (Preliminary) Examination 2019, General Studies Paper II (CSAT), Question 38 — Arithmetic: percentage, ratio, averages, time & work.

ईना अपने माता-पिता के विवाह के 4 वर्ष बाद पैदा हुई । उसकी माता उसके पिता से तीन वर्ष छोटी है और ईना से, जो 13 वर्ष की है, 24 वर्ष बड़ी है । ईना के पिता का किस उम्र में विवाह हुआ था ?

Read this question in English

Ena was born 4 years after her parents’ marriage. Her mother is three years younger than her father and 24 years older than Ena, who is 13 years old. At what age did Ena’s father get married?

(a) 22 years · (b) 23 years · (c) 24 years · (d) 25 years

उत्तर और व्याख्या · explanation in English

Answer: (b) 23 वर्ष

Ena is 13, her mother 37 and her father 40. The marriage took place 13 + 4 = 17 years ago, when the father was 40 − 17 = 23.

  1. Ena = 13; mother = 13 + 24 = 37; father = 37 + 3 = 40.
  2. The marriage was 4 years before Ena's birth: 13 + 4 = 17 years ago.
  3. Father's age at marriage = 40 − 17 = 23 years.

Remember · Fix everyone's present age first, then move all of them back by the same number of years.

Question and answer: UPSC's official GS Paper II (2019, Series A) — paper ↗ · answer key ↗. Explanation: Minimalist IAS, checked 30 Sept 2026 (how we verify). ·

Cite this question: UPSC CSE CSAT 2019, Q38 — minimalistias.com/pyqs/csat/2019/q38

In the UPSC syllabus: Arithmetic: percentage, ratio, averages, time & work › Averages & ages See it and tick it covered →

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