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UPSC CSE CSAT 2019 · Paper II (CSAT) · Question 19 · Arithmetic: percentage, ratio, averages, time & work

राकेश और राजेश ने एक साथ मिल कर 10 गेंदें और 10 रैकेट खरीदे । राकेश ने ₹ 1300 खर्च किए और राजेश ने…

UPSC Civil Services (Preliminary) Examination 2019, General Studies Paper II (CSAT), Question 19 — Arithmetic: percentage, ratio, averages, time & work.

राकेश और राजेश ने एक साथ मिल कर 10 गेंदें और 10 रैकेट खरीदे । राकेश ने ₹ 1300 खर्च किए और राजेश ने ₹ 1500 खर्च किए । यदि प्रत्येक रैकेट की क़ीमत एक गेंद की क़ीमत की तीन गुनी है, तो एक रैकेट की क़ीमत क्या है ?

Read this question in English

Rakesh and Rajesh together bought 10 balls and 10 rackets. Rakesh spent ₹ 1300 and Rajesh spent ₹ 1500. If each racket costs three times a ball does, then what is the price of a racket?

(a) ₹ 70 · (b) ₹ 90 · (c) ₹ 210 · (d) ₹ 240

उत्तर और व्याख्या · explanation in English

Answer: (c) ₹ 210

Only the joint spending matters: ₹2,800 buys 10 balls and 10 rackets, which is the cost of 40 balls. So a ball is ₹70 and a racket ₹210.

  1. Total spent = 1300 + 1500 = ₹2800 for 10 balls and 10 rackets.
  2. Let a ball cost b; a racket costs 3b.
  3. 10b + 10 × 3b = 40b = 2800, so b = 70.
  4. Racket = 3 × 70 = ₹210.
  5. Check: 10 × 70 + 10 × 210 = 700 + 2100 = 2800.

Remember · When the split between buyers is irrelevant, add the spends and solve for the combined purchase.

Question and answer: UPSC's official GS Paper II (2019, Series A) — paper ↗ · answer key ↗. Explanation: Minimalist IAS, checked 30 Sept 2026 (how we verify). ·

Cite this question: UPSC CSE CSAT 2019, Q19 — minimalistias.com/pyqs/csat/2019/q19

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