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UPSC CSE CSAT 2018 · Paper II (CSAT) · Question 34 · Number system

एक संख्या तीन अंकों से बनी है जिनमें मध्य वाला अंक शून्य है और उनका योग 4 है। यदि प्रथम और अंतिम…

UPSC Civil Services (Preliminary) Examination 2018, General Studies Paper II (CSAT), Question 34 — Number system.

CSAT 2018 · Q34

Number system Easy

एक संख्या तीन अंकों से बनी है जिनमें मध्य वाला अंक शून्य है और उनका योग 4 है। यदि प्रथम और अंतिम अंकों का विनिमय (इंटरचेंज) करने पर बनी संख्या स्वयं उसी संख्या से 198 अधिक है, तो प्रथम तथा अंतिम अंकों के बीच अंतर है

Read this question in English

A number consists of three digits of which the middle one is zero and their sum is 4. If the number formed by interchanging the first and last digits is greater than the number itself by 198, then the difference between the first and last digits is

(a) 1 · (b) 2 · (c) 3 · (d) 4

उत्तर और व्याख्या · explanation in English

Answer: (b) 2

Swapping the first and last digits of a three-digit number changes it by 99 × (difference of those digits). 198 ÷ 99 = 2, so the digits differ by 2 — the number is 103, which becomes 301.

  1. Let the number be 100a + c (middle digit 0); interchanged, it is 100c + a.
  2. (100c + a) − (100a + c) = 99(c − a) = 198, so c − a = 2.
  3. With a + c = 4: a = 1 and c = 3, so the number is 103.
  4. Check: 301 − 103 = 198.

Remember · Interchanging the end digits of a three-digit number changes it by 99 × their difference; divide the change by 99.

Question and answer: UPSC's official GS Paper II (2018, Series A) — paper ↗ · answer key ↗. Explanation: Minimalist IAS, checked 30 Sept 2026 (how we verify). ·

Cite this question: UPSC CSE CSAT 2018, Q34 — minimalistias.com/pyqs/csat/2018/q34

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