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UPSC CSE CSAT 2017 · Paper II (CSAT) · Question 30 · Arithmetic: percentage, ratio, averages, time & work

P = (A का 40%) + (B का 65%) तथा Q = (A का 50%) + (B का 50%) जहाँ A, B से बड़ा है। इस सन्दर्भ में…

UPSC Civil Services (Preliminary) Examination 2017, General Studies Paper II (CSAT), Question 30 — Arithmetic: percentage, ratio, averages, time & work.

P = (A का 40%) + (B का 65%) तथा Q = (A का 50%) + (B का 50%) जहाँ A, B से बड़ा है।

इस सन्दर्भ में निम्नलिखित में से कौन-सा कथन सही है?

Read this question in English

P = (40% of A) + (65% of B) and Q = (50% of A) + (50% of B), where A is greater than B.

In this context, which of the following statements is correct?

(a) P is greater than Q. · (b) Q is greater than P. · (c) P is equal to Q. · (d) None of the above can be concluded with certainty.

उत्तर और व्याख्या · explanation in English

Answer: (d) उपर्युक्त में से कोई भी निष्कर्ष निश्चित रूप से नहीं निकाला जा सकता।

P − Q = 0.15B − 0.10A, and its sign depends on how much bigger A is than B. If A is less than 1.5 times B, P is larger; if more, Q is larger; at exactly 1.5 times they are equal. So nothing can be concluded.

  1. P − Q = (0.40A + 0.65B) − (0.50A + 0.50B) = 0.15B − 0.10A.
  2. P > Q when 0.15B > 0.10A, i.e. A < 1.5B; Q > P when A > 1.5B; P = Q when A = 1.5B.
  3. A > B allows all three: A = 1.2, B = 1 gives P > Q; A = 3, B = 1 gives Q > P; A = 1.5, B = 1 gives P = Q.
  4. So the comparison cannot be fixed.

Remember · Subtract the two expressions and study the sign; if it depends on a ratio the question does not fix, the answer is 'cannot be determined'.

Question and answer: UPSC's official GS Paper II (2017, Series A) — paper ↗ · answer key ↗. Explanation: Minimalist IAS, checked 30 Sept 2026 (how we verify). ·

Cite this question: UPSC CSE CSAT 2017, Q30 — minimalistias.com/pyqs/csat/2017/q30

In the UPSC syllabus: Arithmetic: percentage, ratio, averages, time & work › Percentages, profit & loss See it and tick it covered →

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