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UPSC CSE CSAT 2016 · Paper II (CSAT) · Question 74 · Puzzles, arrangements & general mental ability

60 विद्यार्थियों की एक कक्षा में जहाँ लड़कियां लड़कों से दुगुनी संख्या में हैं, कमल (एक लड़का) का…

UPSC Civil Services (Preliminary) Examination 2016, General Studies Paper II (CSAT), Question 74 — Puzzles, arrangements & general mental ability.

60 विद्यार्थियों की एक कक्षा में जहाँ लड़कियां लड़कों से दुगुनी संख्या में हैं, कमल (एक लड़का) का रैंक ऊपर से सत्रहवां है। यदि कमल से पहले नौ लड़कियां हैं, तो कमल के बाद के रैंक में कितने लड़के हैं ?

Read this question in English

In a class of 60 students, where the number of girls is twice that of boys, Kamal, a boy, ranked seventeenth from the top. If there are 9 girls ahead of Kamal, the number of boys in rank after him is:

(a) 13 · (b) 12 · (c) 7 · (d) 3

उत्तर और व्याख्या · explanation in English

Answer: (b) 12

The class has 20 boys and 40 girls. Of the 16 students ahead of Kamal, 9 are girls, so 7 are boys. Leaving out Kamal himself, 20 − 7 − 1 = 12 boys rank below him.

  1. Girls = 2 × boys and the total is 60, so boys = 20 and girls = 40.
  2. Kamal is 17th: 16 students are ahead; 9 are girls, so 7 are boys.
  3. Boys after Kamal = 20 − 7 − 1 = 12.

Remember · In ranking items, split the people ahead by group, then subtract them and the person himself from his group's total.

Question and answer: UPSC's official GS Paper II (2016, Series A) — paper ↗ · answer key ↗. Explanation: Minimalist IAS, checked 30 Sept 2026 (how we verify). ·

Cite this question: UPSC CSE CSAT 2016, Q74 — minimalistias.com/pyqs/csat/2016/q74

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