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UPSC CSE CSAT 2020 · Paper II (CSAT) · Question 51 · Number system

What is the greatest length x such that 3½ m and 8¾ m are integral multiples of x?

UPSC Civil Services (Preliminary) Examination 2020, General Studies Paper II (CSAT), Question 51 — Number system.

CSAT 2020 · Q51

Number system Medium

What is the greatest length x such that 3½ m and 8¾ m are integral multiples of x?

Answer & explanation

Answer: (d) 1¾ m

The greatest length that divides both is their HCF. In quarters of a metre the lengths are 14/4 and 35/4, and HCF(14, 35) = 7, so x = 7/4 = 1¾ m.

  1. 3½ = 14/4 m and 8¾ = 35/4 m.
  2. HCF(14, 35) = 7, so the greatest common length = 7/4 m = 1¾ m.
  3. Check: 3½ ÷ 1¾ = 2 and 8¾ ÷ 1¾ = 5, both whole numbers.

Remember · HCF of fractions: put them over a common denominator, take the HCF of the numerators, keep the denominator.

Question and answer: UPSC's official GS Paper II (2020, Series A) — paper ↗ · answer key ↗. Explanation: Minimalist IAS, checked 30 Sept 2026 (how we verify). ·

Cite this question: UPSC CSE CSAT 2020, Q51 — minimalistias.com/pyqs/csat/2020/q51

In the UPSC syllabus: Number system › Divisibility, remainders, HCF & LCM See it and tick it covered →

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