Rakesh and Rajesh together bought 10 balls and 10 rackets. Rakesh spent ₹ 1300 and Rajesh spent ₹ 1500. If each racket costs three times a ball does, then what is the price of a racket?
Answer & explanation
Answer: (c) ₹ 210
Only the joint spending matters: ₹2,800 buys 10 balls and 10 rackets, which is the cost of 40 balls. So a ball is ₹70 and a racket ₹210.
- Total spent = 1300 + 1500 = ₹2800 for 10 balls and 10 rackets.
- Let a ball cost b; a racket costs 3b.
- 10b + 10 × 3b = 40b = 2800, so b = 70.
- Racket = 3 × 70 = ₹210.
- Check: 10 × 70 + 10 × 210 = 700 + 2100 = 2800.
Remember · When the split between buyers is irrelevant, add the spends and solve for the combined purchase.
Question and answer: UPSC's official GS Paper II (2019, Series A) — paper ↗ · answer key ↗. Explanation: Minimalist IAS, checked 30 Sept 2026 (how we verify). ·