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UPSC CSE CSAT 2016 · Paper II (CSAT) · Question 39 · Geometry & mensuration

A piece of tin is in the form of a rectangle having length 12 cm and width 8 cm. This is used to…

UPSC Civil Services (Preliminary) Examination 2016, General Studies Paper II (CSAT), Question 39 — Geometry & mensuration.

CSAT 2016 · Q39

Geometry & mensuration Easy

A piece of tin is in the form of a rectangle having length 12 cm and width 8 cm. This is used to construct a closed cube. The side of the cube is:

Answer & explanation

Answer: (c) 4 cm

The whole sheet of 12 × 8 = 96 cm² becomes the surface of the cube. A closed cube has six square faces, so 6s² = 96, s² = 16 and each side is 4 cm.

  1. Area of the sheet = 12 × 8 = 96 cm².
  2. Closed cube: 6s² = 96, so s² = 16 and s = 4 cm.
  3. Check: 6 × 4 × 4 = 96.

Remember · Sheet-to-solid problems: the sheet's area equals the surface area of the solid made from it.

Question and answer: UPSC's official GS Paper II (2016, Series A) — paper ↗ · answer key ↗. Explanation: Minimalist IAS, checked 30 Sept 2026 (how we verify). ·

Cite this question: UPSC CSE CSAT 2016, Q39 — minimalistias.com/pyqs/csat/2016/q39

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