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UPSC CSE CSAT 2022 · Paper II (CSAT) · Question 58 · Number system

91×92×93×94×95×96×97×98×99 को 1261 से भाग देने पर शेषफल क्या होगा?

UPSC Civil Services (Preliminary) Examination 2022, General Studies Paper II (CSAT), Question 58 — Number system.

CSAT 2022 · Q58

Number system Easy

91×92×93×94×95×96×97×98×99 को 1261 से भाग देने पर शेषफल क्या होगा?

Read this question in English

What is the remainder when 91 × 92 × 93 × 94 × 95 × 96 × 97 × 98 × 99 is divided by 1261?

(a) 3 · (b) 2 · (c) 1 · (d) 0

उत्तर और व्याख्या · explanation in English

Answer: (d) 0

1261 = 13 × 97. The product contains 91 = 7 × 13 and also 97, so it is a multiple of 1261 and the remainder is 0.

  1. Factorise the divisor: 1261 = 13 × 97.
  2. The product contains 91 = 7 × 13 and the factor 97.
  3. So the product is a multiple of 13 × 97 = 1261, and the remainder is 0.

Remember · Before dividing a big product, factorise the divisor and look for its factors inside the product.

Question and answer: UPSC's official GS Paper II (2022, Series A) — paper ↗ · answer key ↗. Explanation: Minimalist IAS, checked 30 Sept 2026 (how we verify). ·

Cite this question: UPSC CSE CSAT 2022, Q58 — minimalistias.com/pyqs/csat/2022/q58

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