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UPSC CSE CSAT 2022 · Paper II (CSAT) · Question 56 · Geometry & mensuration

किसी वृत्त पर एक-समान दूरी वाले आठ बिन्दु हैं। इन बिन्दुओं को शीर्ष और व्यास को एक भुजा लेकर कितने…

UPSC Civil Services (Preliminary) Examination 2022, General Studies Paper II (CSAT), Question 56 — Geometry & mensuration.

CSAT 2022 · Q56

Geometry & mensuration Easy

किसी वृत्त पर एक-समान दूरी वाले आठ बिन्दु हैं। इन बिन्दुओं को शीर्ष और व्यास को एक भुजा लेकर कितने समकोण त्रिभुज खींचे जा सकते हैं?

Read this question in English

There are eight equidistant points on a circle. How many right-angled triangles can be drawn using these points as vertices and taking the diameter as one side of the triangle?

(a) 24 · (b) 16 · (c) 12 · (d) 8

उत्तर और व्याख्या · explanation in English

Answer: (a) 24

Eight equidistant points form 4 diameters. The angle in a semicircle is a right angle, so each diameter with any of the other 6 points gives a right-angled triangle: 4 × 6 = 24.

  1. With 8 equidistant points, each point has a point exactly opposite it, giving 8 ÷ 2 = 4 diameters.
  2. The angle in a semicircle is a right angle, so a diameter with any third point forms a right-angled triangle.
  3. Each diameter can pair with any of the other 6 points: 4 × 6 = 24 triangles.

Remember · Angle in a semicircle = 90°: count diameters × remaining points.

Question and answer: UPSC's official GS Paper II (2022, Series A) — paper ↗ · answer key ↗. Explanation: Minimalist IAS, checked 30 Sept 2026 (how we verify). ·

Cite this question: UPSC CSE CSAT 2022, Q56 — minimalistias.com/pyqs/csat/2022/q56

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