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UPSC CSE CSAT 2022 · Paper II (CSAT) · Question 17 · Counting, permutations & probability

150 प्रतियोगियों वाली किसी शतरंज टूर्नामेंट में जब-जब कोई खिलाड़ी बाजी हारता है, उसे बाहर कर दिया…

UPSC Civil Services (Preliminary) Examination 2022, General Studies Paper II (CSAT), Question 17 — Counting, permutations & probability.

CSAT 2022 · Q17

Counting, permutations & probability Easy

150 प्रतियोगियों वाली किसी शतरंज टूर्नामेंट में जब-जब कोई खिलाड़ी बाजी हारता है, उसे बाहर कर दिया जाता है। यह निश्चित किया गया है कि कोई भी बाजी बराबरी (टाई/ड्रॉ) पर निर्णीत नहीं होगी। इस पूरे टूर्नामेंट में कितनी बाजियाँ खेली गईं?

Read this question in English

In a tournament of Chess having 150 entrants, a player is eliminated whenever he loses a match. It is given that no match results in a tie/draw. How many matches are played in the entire tournament?

(a) 151 · (b) 150 · (c) 149 · (d) 148

उत्तर और व्याख्या · explanation in English

Answer: (c) 149

Every match has exactly one loser, and every loser is eliminated. The tournament ends when one player is left, so 149 players are eliminated — and that takes exactly 149 matches.

  1. Each match produces exactly one loser, who is eliminated.
  2. To leave a single winner, 150 − 1 = 149 players must be eliminated.
  3. So 149 matches are played.
  4. Check: with 4 players, 2 semi-finals + 1 final = 3 = 4 − 1 matches.

Remember · Knockout tournament with n players: always n − 1 matches, whatever the byes.

Question and answer: UPSC's official GS Paper II (2022, Series A) — paper ↗ · answer key ↗. Explanation: Minimalist IAS, checked 30 Sept 2026 (how we verify). ·

Cite this question: UPSC CSE CSAT 2022, Q17 — minimalistias.com/pyqs/csat/2022/q17

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