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CSAT 2021 paper

UPSC CSE CSAT 2021 · Paper II (CSAT) · Question 50 · Puzzles, arrangements & general mental ability

अनुक्रम 2, 7, 22, 67, 202, X, 1822 में ‘X’ का मान क्या है ?

UPSC Civil Services (Preliminary) Examination 2021, General Studies Paper II (CSAT), Question 50 — Puzzles, arrangements & general mental ability.

अनुक्रम 2, 7, 22, 67, 202, X, 1822 में ‘X’ का मान क्या है ?

Read this question in English

What is the value of ‘X’ in the sequence 2, 7, 22, 67, 202, X, 1822?

(a) 603 · (b) 605 · (c) 607 · (d) 608

उत्तर और व्याख्या · explanation in English

Answer: (c) 607

Every term is three times the previous one plus 1. So X = 202 × 3 + 1 = 607, and 607 × 3 + 1 = 1822 confirms it.

  1. 2 × 3 + 1 = 7, 7 × 3 + 1 = 22, 22 × 3 + 1 = 67, 67 × 3 + 1 = 202 — each term is 3 × previous + 1.
  2. X = 202 × 3 + 1 = 607.
  3. Check: 607 × 3 + 1 = 1822, the next term.

Remember · When terms roughly triple, test '× 3 ± k', and always verify with the term after the blank.

Question and answer: UPSC's official GS Paper II (2021, Series A) — paper ↗ · answer key ↗. Explanation: Minimalist IAS, checked 30 Sept 2026 (how we verify). ·

Cite this question: UPSC CSE CSAT 2021, Q50 — minimalistias.com/pyqs/csat/2021/q50

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