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UPSC CSE CSAT 2018 · Paper II (CSAT) · Question 59 · Puzzles, arrangements & general mental ability

निम्नलिखित अनुक्रम पर विचार कीजिए : 4/12/95, 1/1/96, 29/1/96, 26/2/96, ... इस अनुक्रम का अगला पद…

UPSC Civil Services (Preliminary) Examination 2018, General Studies Paper II (CSAT), Question 59 — Puzzles, arrangements & general mental ability.

निम्नलिखित अनुक्रम पर विचार कीजिए :

4/12/95, 1/1/96, 29/1/96, 26/2/96, ...

इस अनुक्रम का अगला पद क्या होगा?

Read this question in English

Consider the sequence given below:

4/12/95, 1/1/96, 29/1/96, 26/2/96, ....

What is the next term of the series?

(a) 24/3/96 · (b) 25/3/96 · (c) 26/3/96 · (d) 27/3/96

उत्तर और व्याख्या · explanation in English

Answer: (b) 25/3/96

Each date is 28 days after the one before. 26 February 1996 plus 28 days is 25 March, because 1996 is a leap year and February has 29 days.

  1. 4 December 1995 to 1 January 1996: 27 days to the end of December + 1 = 28 days.
  2. 1 January to 29 January: 28 days; 29 January to 26 February: 2 + 26 = 28 days.
  3. 1996 is divisible by 4, so February 1996 has 29 days.
  4. 26 February + 28 days: 3 days to 29 February, then 25 more — 25 March 1996.

Remember · In date sequences, find the constant gap in days and watch for leap years when crossing February.

Question and answer: UPSC's official GS Paper II (2018, Series A) — paper ↗ · answer key ↗. Explanation: Minimalist IAS, checked 30 Sept 2026 (how we verify). ·

Cite this question: UPSC CSE CSAT 2018, Q59 — minimalistias.com/pyqs/csat/2018/q59

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