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UPSC CSE CSAT 2017 · Paper II (CSAT) · Question 51 · Number system

99 तथा 1000 के बीच ऐसी कितनी संख्याएँ हैं, जिनमें अंक 8 इकाई स्थान पर है?

UPSC Civil Services (Preliminary) Examination 2017, General Studies Paper II (CSAT), Question 51 — Number system.

CSAT 2017 · Q51

Number system X-Ray · Core #4 Easy

99 तथा 1000 के बीच ऐसी कितनी संख्याएँ हैं, जिनमें अंक 8 इकाई स्थान पर है?

Read this question in English

How many numbers are there between 99 and 1000 such that the digit 8 occupies the units place?

(a) 64 · (b) 80 · (c) 90 · (d) 104

उत्तर और व्याख्या · explanation in English

Answer: (c) 90

Numbers between 99 and 1000 are the 3-digit numbers 100 to 999. With 8 fixed in the units place, the hundreds digit has 9 choices and the tens digit 10 choices, giving 9 × 10 = 90.

  1. Numbers strictly between 99 and 1000: 100 to 999.
  2. Units digit fixed as 8.
  3. Hundreds digit: 1–9 (9 ways); tens digit: 0–9 (10 ways).
  4. Count = 9 × 10 = 90.
  5. Check: 108, 118, …, 998 rise in steps of 10, so the count is (998 − 108) ÷ 10 + 1 = 90.

Remember · Fix the given digit, then multiply the free choices for the other places — the leading digit cannot be 0.

Question and answer: UPSC's official GS Paper II (2017, Series A) — paper ↗ · answer key ↗. Explanation: Minimalist IAS, checked 30 Sept 2026 (how we verify). ·

Cite this question: UPSC CSE CSAT 2017, Q51 — minimalistias.com/pyqs/csat/2017/q51

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