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UPSC CSE CSAT 2026 · Paper II (CSAT) · Question 67 · Logical & analytical reasoning

If ZERO is encoded as ADSN, then how do you encode STOP?

UPSC Civil Services (Preliminary) Examination 2026, General Studies Paper II (CSAT), Question 67 — Logical & analytical reasoning.

CSAT 2026 · Q67

Logical & analytical reasoning Easy Provisional key

If ZERO is encoded as ADSN, then how do you encode STOP?

Answer & explanation

Answer: (b) TSPO

Letters shift alternately forward and back by one: Z → A (+1), E → D (−1), R → S (+1), O → N (−1). Applying +1, −1, +1, −1 to S, T, O, P gives T, S, P, O.

  1. Z + 1 = A, E − 1 = D, R + 1 = S, O − 1 = N.
  2. S + 1 = T, T − 1 = S, O + 1 = P, P − 1 = O.
  3. STOP → TSPO.

Remember · Coding items: write the shift for each letter position; alternating patterns are common.

Question and answer: UPSC's provisional GS Paper II (2026, Series A) — paper ↗ · answer key ↗. Explanation: Minimalist IAS, checked 30 Sept 2026 (how we verify). ·

Cite this question: UPSC CSE CSAT 2026, Q67 — minimalistias.com/pyqs/csat/2026/q67

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