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CSAT 2023 paper

UPSC CSE CSAT 2023 · Paper II (CSAT) · Question 55 · Puzzles, arrangements & general mental ability

What is the middle term of the sequence Z, Z, Y, Y, Y, X, X, X, X, W, W, W, W, W, …, A?

UPSC Civil Services (Preliminary) Examination 2023, General Studies Paper II (CSAT), Question 55 — Puzzles, arrangements & general mental ability.

What is the middle term of the sequence Z, Z, Y, Y, Y, X, X, X, X, W, W, W, W, W, …, A?

Answer & explanation

Answer: (b) I

Z appears 2 times, Y 3 times and so on, up to A 27 times, so there are 377 terms and the middle one is the 189th. The first k letters fill k(k + 3)/2 places; for k = 18 this is exactly 189, so the middle term is the 18th letter counted from Z, which is I.

  1. The kth letter from Z appears k + 1 times: Z (2), Y (3), …, A (27).
  2. Total terms = 2 + 3 + … + 27 = 377, so the middle term is the (377 + 1)/2 = 189th.
  3. The first k letters take up 2 + 3 + … + (k + 1) = k(k + 3)/2 places.
  4. k = 17 gives 170 and k = 18 gives 189, so the 189th term is the last copy of the 18th letter from Z.
  5. Counting back from Z: Z, Y, X, W, V, U, T, S, R, Q, P, O, N, M, L, K, J, I — the 18th is I.

Remember · For blocks of growing length, find the total, locate the middle position, then use running totals to see which block holds it.

Question and answer: UPSC's official GS Paper II (2023, Series A) — paper ↗ · answer key ↗. Explanation: Minimalist IAS, checked 30 Sept 2026 (how we verify). ·

Cite this question: UPSC CSE CSAT 2023, Q55 — minimalistias.com/pyqs/csat/2023/q55

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