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CSAT 2022 paper

UPSC CSE CSAT 2022 · Question 80 · Arithmetic: percentage, ratio, averages, time & work

The average weight of A, B, C is 40 kg, the average weight of B, D, E is 42 kg and the weight of F…

The average weight of A, B, C is 40 kg, the average weight of B, D, E is 42 kg and the weight of F is equal to that of B. What is the average weight of A, B, C, D, E and F?

Answer & explanation

Answer: (c) 41 kg

A + B + C = 120 and B + D + E = 126. Since F weighs the same as B, the six weights total 120 + 126 = 246 kg, and the average is 41 kg even though B itself is unknown.

  1. A + B + C = 3 × 40 = 120 kg and B + D + E = 3 × 42 = 126 kg.
  2. Since F = B, A + B + C + D + E + F = (A + B + C) + (F + D + E) = 120 + (B + D + E) = 120 + 126 = 246 kg.
  3. Average = 246 ÷ 6 = 41 kg.

Remember · Before answering ‘cannot be determined’, check whether the unknown cancels — here F = B fills the gap exactly.

Question and answer: UPSC's official GS Paper II (2022, Series A) — paper ↗ · answer key ↗. Explanation: Minimalist IAS, checked 30 Sept 2026 (how we verify). ·

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