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UPSC CSE CSAT 2020 · Paper II (CSAT) · Question 10 · Number system

How many five-digit prime numbers can be obtained by using all the digits 1, 2, 3, 4 and 5 without…

UPSC Civil Services (Preliminary) Examination 2020, General Studies Paper II (CSAT), Question 10 — Number system.

CSAT 2020 · Q10

Number system X-Ray · Core #4 Easy

How many five-digit prime numbers can be obtained by using all the digits 1, 2, 3, 4 and 5 without repetition of digits?

Answer & explanation

Answer: (a) Zero

Every such number uses the digits 1 to 5 once, so its digit sum is 15. A digit sum of 15 makes every one of these numbers divisible by 3, so none can be prime.

  1. Digit sum = 1 + 2 + 3 + 4 + 5 = 15, whatever the order.
  2. 15 is divisible by 3, so every such five-digit number is divisible by 3.
  3. A number greater than 3 that is divisible by 3 is not prime, so the count is zero.

Remember · Before listing permutations for primes, check the digit sum: if it is a multiple of 3, no arrangement is prime.

Question and answer: UPSC's official GS Paper II (2020, Series A) — paper ↗ · answer key ↗. Explanation: Minimalist IAS, checked 30 Sept 2026 (how we verify). ·

Cite this question: UPSC CSE CSAT 2020, Q10 — minimalistias.com/pyqs/csat/2020/q10

In the UPSC syllabus: Number system › Number properties & sequences See it and tick it covered →

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