Minimalist IAS
Sign up
English हिंदी
CSAT 2019 paper

UPSC CSE CSAT 2019 · Paper II (CSAT) · Question 52 · Arithmetic: percentage, ratio, averages, time & work

In a group of 15 people; 7 can read French, 8 can read English while 3 of them can read neither of…

UPSC Civil Services (Preliminary) Examination 2019, General Studies Paper II (CSAT), Question 52 — Arithmetic: percentage, ratio, averages, time & work.

CSAT 2019 · Q52

Arithmetic: percentage, ratio, averages, time & work X-Ray · Core #5 Easy

In a group of 15 people; 7 can read French, 8 can read English while 3 of them can read neither of these two languages. The number of people who can read exactly one language is

Answer & explanation

Answer: (b) 9

Twelve people read at least one language. French and English readers add to 15, so 3 read both, and 12 − 3 = 9 read exactly one.

  1. At least one language = 15 − 3 = 12.
  2. Both = 7 + 8 − 12 = 3.
  3. Exactly one = 12 − 3 = 9 (French only 4, English only 5).

Remember · Exactly one = (at least one) − (both); get 'both' from A + B − (at least one).

Question and answer: UPSC's official GS Paper II (2019, Series A) — paper ↗ · answer key ↗. Explanation: Minimalist IAS, checked 30 Sept 2026 (how we verify). ·

Cite this question: UPSC CSE CSAT 2019, Q52 — minimalistias.com/pyqs/csat/2019/q52

In the UPSC syllabus: Arithmetic: percentage, ratio, averages, time & work › Word problems & equations See it and tick it covered →

Timed · 30 minutes Take CSAT Arithmetic: percentage, ratio, averages, time & work · Set 4 as a test This question is in it — with UPSC's marking and an instant score. Start the set

More on Arithmetic: percentage, ratio, averages, time & work

All Arithmetic: percentage, ratio, averages, time & work questions →

From the UPSC Blog