Minimalist IAS
CSAT 2019 paper

UPSC CSE CSAT 2019 · Paper II (CSAT) · Question 72 · Counting, permutations & probability

किसी घन के प्रत्येक फलक को काले या सफेद रंग से रँगा जा सकता है । उस घन को कितने विभिन्न तरीकों से…

UPSC Civil Services (Preliminary) Examination 2019, General Studies Paper II (CSAT), Question 72 — Counting, permutations & probability.

CSAT 2019 · Q72

Counting, permutations & probability Medium

किसी घन के प्रत्येक फलक को काले या सफेद रंग से रँगा जा सकता है । उस घन को कितने विभिन्न तरीकों से रँगा जा सकता है ?

Read this question in English

Each face of a cube can be painted in black or white colours. In how many different ways can the cube be painted?

(a) 9 · (b) 10 · (c) 11 · (d) 12

उत्तर और व्याख्या · explanation in English

Answer: (b) 10

Treating paintings that can be turned into one another as the same, count by the number of black faces: 0, 1, 5 or 6 black faces give one pattern each, while 2, 3 or 4 give two each. Total 1 + 1 + 2 + 2 + 2 + 1 + 1 = 10.

  1. Count by the number of black faces; rotations of the cube give the same painting.
  2. 0 black: 1 way. 1 black: 1 way (any face can be turned to the top).
  3. 2 black: adjacent or opposite → 2 ways.
  4. 3 black: all three meeting at a corner, or in a band (two opposite faces plus one between) → 2 ways.
  5. 4 black = 2 white → 2 ways; 5 black → 1 way; 6 black → 1 way.
  6. Total = 1 + 1 + 2 + 2 + 2 + 1 + 1 = 10.

Remember · For two-colour cube patterns, count by faces of one colour; k and 6 − k faces give the same count.

Question and answer: UPSC's official GS Paper II (2019, Series A) — paper ↗ · answer key ↗. Explanation: Minimalist IAS, checked 30 Sept 2026 (how we verify). ·

Cite this question: UPSC CSE CSAT 2019, Q72 — minimalistias.com/pyqs/csat/2019/q72

In the UPSC syllabus: Counting, permutations & probability › Counting figures & cases See it and tick it covered →

Timed · 35 minutes Take CSAT Counting, permutations & probability · Set 1 as a test This question is in it — with UPSC's marking and an instant score. Start the set

More on Counting, permutations & probability

All Counting, permutations & probability questions →