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UPSC CSE CSAT 2017 · Paper II (CSAT) · Question 18 · Puzzles, arrangements & general mental ability

52 विद्यार्थियों की एक कक्षा में 15 विद्यार्थी अनुत्तीर्ण हुए। अनुत्तीर्ण विद्यार्थियों के नाम हटा…

UPSC Civil Services (Preliminary) Examination 2017, General Studies Paper II (CSAT), Question 18 — Puzzles, arrangements & general mental ability.

52 विद्यार्थियों की एक कक्षा में 15 विद्यार्थी अनुत्तीर्ण हुए। अनुत्तीर्ण विद्यार्थियों के नाम हटा देने के बाद, योग्यता-क्रम की एक सूची बनाई गई है जिसमें रमेश का स्थान ऊपर से 22वाँ है। नीचे से उसका स्थान कौन-सा है?

Read this question in English

15 students failed in a class of 52. After removing the names of failed students, a merit order list has been prepared in which the position of Ramesh is 22nd from the top. What is his position from the bottom?

(a) 18th · (b) 17th · (c) 16th · (d) 15th

उत्तर और व्याख्या · explanation in English

Answer: (c) 16वाँ

Only the 52 − 15 = 37 students who passed are in the merit list. With 21 above Ramesh, 37 − 22 = 15 are below him, so he is 16th from the bottom.

  1. Students in the merit list = 52 − 15 = 37.
  2. Position from bottom = total − position from top + 1 = 37 − 22 + 1 = 16.
  3. Check: 21 above + Ramesh + 15 below = 37.

Remember · Rank from top + rank from bottom = total + 1 — but first count only those actually in the list.

Question and answer: UPSC's official GS Paper II (2017, Series A) — paper ↗ · answer key ↗. Explanation: Minimalist IAS, checked 30 Sept 2026 (how we verify). ·

Cite this question: UPSC CSE CSAT 2017, Q18 — minimalistias.com/pyqs/csat/2017/q18

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