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UPSC CSE CSAT 2025 · Paper II (CSAT) · Question 56 · Logical & analytical reasoning

If NO is coded as 210, NOT is coded as 4200 and NOTE is coded as 21000, then how is NOTES coded?

UPSC Civil Services (Preliminary) Examination 2025, General Studies Paper II (CSAT), Question 56 — Logical & analytical reasoning.

CSAT 2025 · Q56

Logical & analytical reasoning Easy

If NO is coded as 210, NOT is coded as 4200 and NOTE is coded as 21000, then how is NOTES coded?

Answer & explanation

Answer: (a) 399000

The code multiplies the alphabet positions of the letters: 14 × 15 = 210, then × 20 = 4200, then × 5 = 21000. Adding S (19) gives 21000 × 19 = 399000.

  1. Alphabet positions: N = 14, O = 15, T = 20, E = 5, S = 19.
  2. NO = 14 × 15 = 210. NOT = 210 × 20 = 4200. NOTE = 4200 × 5 = 21000. The code is the product of the positions.
  3. NOTES = 21000 × 19 = 399000.
  4. Check: 4200 ÷ 210 = 20 (T) and 21000 ÷ 4200 = 5 (E), confirming the rule.

Remember · When a code grows as letters are added, divide consecutive codes: the ratio gives each new letter's value (here its alphabet position).

Question and answer: UPSC's official GS Paper II (2025, Series A) — paper ↗ · answer key ↗. Explanation: Minimalist IAS, checked 30 Sept 2026 (how we verify). ·

Cite this question: UPSC CSE CSAT 2025, Q56 — minimalistias.com/pyqs/csat/2025/q56

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