Minimalist IAS
CSAT 2024 paper

UPSC CSE CSAT 2024 · Paper II (CSAT) · Question 5 · Puzzles, arrangements & general mental ability

What is the least possible number of cuts required to cut a cube into 64 identical pieces?

UPSC Civil Services (Preliminary) Examination 2024, General Studies Paper II (CSAT), Question 5 — Puzzles, arrangements & general mental ability.

What is the least possible number of cuts required to cut a cube into 64 identical pieces?

Answer & explanation

Answer: (b) 9

64 identical pieces means a 4 × 4 × 4 arrangement. Each direction needs 3 cuts to make 4 slices, so the least number is 3 + 3 + 3 = 9.

  1. With a, b and c straight cuts in the three directions, the number of pieces is (a + 1)(b + 1)(c + 1).
  2. We need (a + 1)(b + 1)(c + 1) = 64 with a + b + c as small as possible; the total is least when the three factors are equal: 4 × 4 × 4.
  3. So a = b = c = 3, and the number of cuts = 3 + 3 + 3 = 9.
  4. Check: other splits cost more, e.g. 8 × 4 × 2 needs 7 + 3 + 1 = 11 cuts.

Remember · Pieces = (a + 1)(b + 1)(c + 1) for a, b, c cuts in three directions; cuts are fewest when the factors are equal.

Question and answer: UPSC's official GS Paper II (2024, Series A) — paper ↗ · answer key ↗. Explanation: Minimalist IAS, checked 30 Sept 2026 (how we verify). ·

Cite this question: UPSC CSE CSAT 2024, Q5 — minimalistias.com/pyqs/csat/2024/q5

In the UPSC syllabus: Puzzles, arrangements & general mental ability › Cubes, dice & figures See it and tick it covered →

Timed · 30 minutes Take CSAT Puzzles, arrangements & general mental ability · Set 5 as a test This question is in it — with UPSC's marking and an instant score. Start the set

More on Puzzles, arrangements & general mental ability

All Puzzles, arrangements & general mental ability questions →