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UPSC CSE CSAT 2022 · Question 24 · Counting, permutations & probability

The letters A, B, C, D and E are arranged in such a way that there are exactly two letters between…

CSAT 2022 · Q24

Counting, permutations & probability Easy

The letters A, B, C, D and E are arranged in such a way that there are exactly two letters between A and E. How many such arrangements are possible?

Answer & explanation

Answer: (c) 24

In a row of five, A and E can stand only at places 1 and 4 or 2 and 5, in either order: 4 ways. The other three letters then fill the remaining places in 3! = 6 ways, giving 24.

  1. Number the places 1 to 5. Exactly two letters between A and E means A and E occupy places (1, 4) or (2, 5): 2 choices of places.
  2. A and E can swap within the chosen places: 2 × 2 = 4 ways.
  3. B, C and D fill the other three places in 3! = 6 ways.
  4. Total = 4 × 6 = 24.

Remember · Place the constrained pair first (positions × internal order), then arrange the remaining items freely.

Question and answer: UPSC's official GS Paper II (2022, Series A) — paper ↗ · answer key ↗. Explanation: Minimalist IAS, checked 30 Sept 2026 (how we verify). ·

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