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UPSC CSE CSAT 2019 · Question 14 · Counting, permutations & probability

The number of parallelograms that can be formed from a set of four parallel lines intersecting…

CSAT 2019 · Q14

Counting, permutations & probability Easy

The number of parallelograms that can be formed from a set of four parallel lines intersecting another set of four parallel lines, is

Answer & explanation

Answer: (d) 36

Every choice of two lines from each family encloses exactly one parallelogram, so the count is 4C2 × 4C2 = 6 × 6 = 36.

  1. A parallelogram needs two lines from the first set and two from the second.
  2. Ways to choose 2 lines out of 4 = 4C2 = 6, for each set.
  3. Parallelograms = 6 × 6 = 36.

Remember · m parallel lines crossing n parallel lines form mC2 × nC2 parallelograms.

Question and answer: UPSC's official GS Paper II (2019, Series A) — paper ↗ · answer key ↗. Explanation: Minimalist IAS, checked 30 Sept 2026 (how we verify). ·

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