Minimalist IAS
CSAT 2020 paper

UPSC CSE CSAT 2020 · Question 53 · Number system

The recurring decimal representation 1.272727... is equivalent to

CSAT 2020 · Q53

Number system Easy

The recurring decimal representation 1.272727... is equivalent to

Answer & explanation

Answer: (b) 14/11

The repeating block 27 has two digits, so 0·2727... = 27/99 = 3/11. Adding the whole part gives 1 + 3/11 = 14/11.

  1. Let x = 1·2727...; then 100x = 127·2727...
  2. 100x − x = 126, so x = 126/99 = 14/11.
  3. Check: 14 ÷ 11 = 1·2727...

Remember · A pure recurring decimal 0·(ab) repeating = ab/99; handle the whole-number part separately.

Question and answer: UPSC's official GS Paper II (2020, Series A) — paper ↗ · answer key ↗. Explanation: Minimalist IAS, checked 30 Sept 2026 (how we verify). ·

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