Minimalist IAS
CSAT 2024 paper

UPSC CSE CSAT 2024 · Question 55 · Number system

Let p and q be positive integers satisfying p < q and p + q = k. What is the smallest value of k…

CSAT 2024 · Q55

Number system Easy

Let p and q be positive integers satisfying p < q and p + q = k. What is the smallest value of k that does not determine p and q uniquely?

Answer & explanation

Answer: (c) 5

For k = 3 and k = 4 there is only one pair with p < q: (1, 2) and (1, 3). For k = 5 there are two, (1, 4) and (2, 3), so 5 is the smallest k that does not fix p and q.

  1. k = 3: only (1, 2). Unique.
  2. k = 4: only (1, 3), since (2, 2) breaks p < q. Unique.
  3. k = 5: (1, 4) and (2, 3). Not unique.
  4. So the smallest such k is 5.

Remember · For a ‘smallest value’ question, test the options in increasing order and stop at the first that works.

Question and answer: UPSC's official GS Paper II (2024, Series A) — paper ↗ · answer key ↗. Explanation: Minimalist IAS, checked 30 Sept 2026 (how we verify). ·

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