How many numbers are there between 99 and 1000 such that the digit 8 occupies the units place?

Answer: (c) 90

Numbers between 99 and 1000 are the 3-digit numbers 100 to 999. With 8 fixed in the units place, the hundreds digit has 9 choices and the tens digit 10 choices, giving 9 × 10 = 90.

1. Numbers strictly between 99 and 1000: 100 to 999.
2. Units digit fixed as 8.
3. Hundreds digit: 1–9 (9 ways); tens digit: 0–9 (10 ways).
4. Count = 9 × 10 = 90.
5. Check: 108, 118, …, 998 rise in steps of 10, so the count is (998 − 108) ÷ 10 + 1 = 90.

Remember · Fix the given digit, then multiply the free choices for the other places — the leading digit cannot be 0.

Question and answer: UPSC's official GS Paper II (2017, Series A) — paper ↗ · answer key ↗. Explanation: Minimalist IAS, checked 30 Sept 2026 (how we verify). · Report an error